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Selecting a Cooling Fan

Selecting the correct fan is as important as deciding how that fan is controlled. Generally the OEM fans are of the best design and quality, but there are a number of parameters that should be looked at when choosing a fan. Use the highest blade diameter possible, all things being equal, an 18" diameter fan will outflow a 16" fan by nearly 20%, moreover, a larger radiator surface area is covered. Secondly, a high peak to average motor current indicates a high efficiency motor, a motor with a 3:1 peak to average current ratio will consume 1/3 less current than one with a 2:1 ratio for the same horsepower output. And finally, a 50% blade to open area ratio provides the highest flow rate per horsepower, and both the high peak to average current motor and the high blade to open air ratio blade provide higher backpressure performance. . The table below will allow you to determine if what you are buying provides the airflow that a given manufacturer claims. Note that a less than 50% blade to open air ratio, as well as a non-optimum blade design will flow less than the number given. Simply enter the data into the red boxes below to indicate the calculated cfm. A mathematical analysis is presented below the spreadsheet.

Hardware

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Nomenclature:

Vin: Input voltage

Iin: Average input current

Ipeak/Irun: Peak to average current (most oems:3 or 4, most aftermarket 2, Ramchargers 5)

Fan D: Fan diameter

Motor D : Motor diameter

 

 

Compressible Fluid Flow of an Electric Cooling Fan

Brian L. Baskin

Delta Current Control

All Rights Reserved

 

The Work of Kinetic Energy

The work output of a fan, neglecting turbulence losses is characterized by the equation:

W = ½mv2 equation 1.0

Where W represents the work accomplished in joules, m represents the total mass of the liquid or gas accelerated in kilograms, and v represents the change in velocity of the gas in meters per second. The power consumed is represented by the first derivative of work with respect to time and is shown below:

P = (½mv2)/t equation 2.0

P = (½(m/t)v2) equation 2.1

Where P represents the power needed to do an amount of work in joules per second (watt) and t represents time in seconds.

The mass can be represented as volume if the density of the material is known. The density of atmospheric gas, primarily nitrogen, oxygen, and argon is equal to one cubic meter per kilogram or 35.31 cubic feet per kilogram. One cfm then equals 1/2119 cubic meters per second or 1/2119 kilograms per second.

The terminal velocity is a product of cfm and outlet area, the output area of a fan is characterized by the equation:

A = (1/39.37)2(p D2/4) = D2/1974 equation 3.0

Where A represents the output area in square meters and D represents the total blade diameter in inches.

Terminal velocity can then be represented by volume in cubic meters per second divided by the area and the equation:

v = (cfm/2119)/(D2/1974) = .932*cfm/D2 equation 4.0

The work over time is then represented in imperial units by the equation:

P = ½(cfm/2119)(.932*cfm/D2)2 equation 5.0

cfm = (4883* P*D4)1/3

Keep in mind that this represents an ideal fan without turbulence and with uniform velocity.

 

Motor Efficiency

Unfortunately, not all of the power a motor receives is transformed into work. Resistive, magnetic, and frictional losses all serve to lower the efficiency of a motor.

Both magnetic and resistive losses can be represented as a single bulk resistance in series with the load.

The ratio of bulk resistance to total series resistance can be found by comparing the running current to the locked-rotor current.

RB/RT = IR/IP equation 6.0

RB = (IR/IP)RT equation 6.1

The ratio of load resistance to total series resistance is then the difference between the total series resistance and the bulk resistance.

RL = RT(1-IR/IP) equation 7.0

The ratio of bulk resistance to load resistance is then:

RB/RL = (IR/IP)/(1-IR/IP) equation 8.0

RB = RL(IR/IP)/(1-IR/IP) equation 8.1

RB = RLIR/(IP -IR) equation 8.2

The ratio of Voltage across the load to the total voltage is proportional to the load resistance divided by the total resistance and is represented by the equation:

VL/VT = (1-IR/IP) equation 9.0

The power received by the load is represented by the equation below:

PL = (Vin)(1-IR/IP)(IT) equation 10.0

Frictional losses, proportional to rpm are represented by the equation:

PF = k(rpm/rpmmx) equation 11.0

Where k is a friction constant. Because bulk to total resistance is dependant on the same rpm to rpm max ratio, equation 11.0 can be represented by:

PF = k(1-IR/IP) equation 11.1

The total cfm is then:

cfm = (4883* (Vin)(1-IR/IP)(IT)(1- k(1-IR/IP))*D4)1/3